Answer:
Step-by-step explanation:
let us take any two points on the line say (-3,-6) and (3,8)
[tex]slope=\frac{-8-(-6)}{3-(-3)} =\frac{-8+6}{3+3} =\frac{-2}{6} =\frac{-1}{3} \\eq.~of~line~is ~y+6=-\frac{1}{3} (x+3)\\3y+18=-x-3\\x+3y=-3-18\\or~x+3y=-21\\or 3y=-x-21\\or~y=-\frac{1}{3} x-7[/tex]
