For this case we have that by definition, the density is given by:
[tex]d = \frac {M} {V}[/tex]
Where:
M: It is the mass of the diamond
V: It is the volume of the diamond
According to the data of the statement we have:
[tex]d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g[/tex]
So the volume is:
[tex]V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3[/tex]
Thus, the volume of the diamond is approximately [tex]0.03 \ cm ^ 3[/tex]
Answer:
[tex]0.03 \ cm ^ 3[/tex]
