Given:
It is given that the lines AB and DE are parallel.
We need to determine the value of x.
Value of x:
Let us use the property of similar triangles.
Thus, using the similar triangles, the corresponding sides of the triangle is given by
[tex]\frac{AB}{ED}=\frac{BC}{CD}[/tex]
Substituting AB = 10, ED = 6, BC = 14 and CD = x in the above expression, we get;
[tex]\frac{10}{6}=\frac{14}{x}[/tex]
Cross multiplying, we have;
[tex]10x=14\times 6[/tex]
[tex]10x=84[/tex]
[tex]x=8.4[/tex]
Thus, the value of x is 8.4
