A solution with a pH of 11 has a [H+] of [tex]1.0\times 10^{-11}[/tex]
Option B is correct option.
Step-by-step explanation:
A solution with a pH of 11 has a [H+] of= ?
pH=?
Concentration of H+ [H+]= ?
Formula used: [tex]pH=-log[H+][/tex]
Putting values and finding [H+]
[tex]pH=-log[H+]\\\,[H+]\,=10^{-pH}\\\,[H+]\,=10^{-11}\\\,[H+]\,=1.0\times 10^{-11}[/tex]
So, A solution with a pH of 11 has a [H+] of [tex]1.0\times 10^{-11}[/tex]
Option B is correct option.
