Step-by-step explanation:
Given equation of circle is:
[tex]{(x +6)}^{2} + {(y - 1)}^{2} = 25\\
{(x +6)}^{2} + {(y - 1)}^{2} = {5}^{2} \\ equating \: it \: with \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ we \: find: \\ - h = 6 \implies \: h = - 6\\ - k = - 1\implies \: k= 1 \\ \therefore \: center = (h, \: k) \\ \red{ \boxed{\bold {\therefore \: center = (-6, \: 1)}}} \\ \\ \: \: \: \purple{ \boxed{\bold {radius \: r = 5 \: units}}}[/tex]
