kwgw2002 kwgw2002
  • 03-03-2020
  • Mathematics
contestada

Problems 13 and 14.

Problems 13 and 14 class=

Respuesta :

sreeram0407 sreeram0407
  • 03-03-2020

Answer:

13) 0

Step-by-step explanation:

Answer Link
igoroleshko156
igoroleshko156 igoroleshko156
  • 03-03-2020

Answer:

#13:  0

#14:  -99

Step-by-step explanation:

#13:  g(x) = 2x^3 - 5x^2 + 4x - 1;  x = 1

Step 1:  Substitute 1 for x

2(1)^3 - 5(1)^2 + 4(1) - 1

2(1) - 5(1) + 4 - 1

2 - 5 + 4 - 1

0

Answer:  0

#14:  h(x) = x^4 + 7x^3 + x^2 - 2x - 6;  x = -3

Step 1:  Substitute -3 for x

(-3)^4 + 7(-3)^3 + (-3)^2 - 2(-3) - 6

81 + 7(-27) + 9 + 6 - 6

81 - 189 + 9 + 6 - 6

-99

Answer:  -99

Answer Link

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