Answer:
The 4th term in the sequence is 7.
Step-by-step explanation:
Assuming
[tex]$c_n = c_{n-1}*\frac{1}{2} $[/tex]
The 1st term of the sequence is
[tex]c_1 = 56,[/tex]
the 2nd term is
[tex]$c_2 = 56*\frac{1}{2} = 28, $[/tex]
the 3rd term is
[tex]$c_3 = 28*\frac{1}{2} =14, $[/tex]
and the 4th term is
[tex]$\boxed{c_4 = 14*\frac{1}{2} = 7}. $[/tex]
