Answer:
[tex]10[/tex]
Step-by-step explanation:
Combinations : When there are total [tex]n[/tex] choices and you have to choose [tex]k[/tex]of them (in any order)
The possible ways [tex]= \ ^n{c_{k}} = \frac{n!}{k!(n-k)!}[/tex]
Here total chances [tex]=5[/tex]
and we have to choose [tex]2[/tex]of them.
Possible ways[tex]=\ ^5{c_{2}}[/tex]
[tex]=&\frac{5!}{2!(5-2)!} = \frac{5!}{3! 2!} \\\\=&\frac{5 \times 4\times 3!}{3! 2!} = \frac{5 \times 4}{2} = 10[/tex]
