Answer:
[tex]x=\frac{5(+/-)\sqrt{25-8a}} {2a}[/tex]
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]ax^{2} -5x+2=0[/tex]
so
[tex]a=a\\b=-5\\c=2[/tex]
substitute in the formula
[tex]x=\frac{5(+/-)\sqrt{-5^{2}-4(a)(2)}}{2a}[/tex]
[tex]x=\frac{5(+/-)\sqrt{25-8a}} {2a}[/tex]
