contestada

18.1-1. Diffusion of Methane Through Helium. A gas of CH4 and He is contained in a tube at 101.32 kPa pressure and 298 K. At one point, the partial pressure of methane is pA1 = 60.79 kPa, and at a point 0.02 m distance away, pA2 = 20.26 kPa. If the total pressure is constant throughout the tube, calculate the flux of CH4 (methane) at steady state for equimolar counterdiffusion.

Respuesta :

Answer:

5.521 Ɨ 10ā»Ā² mol/mĀ².s

Explanation:

Given:

Pressure of the Methane and Helium gas = 101.32 kPa

Temperature of the Methane and Helium gas = 298 K

Partial pressure of Methane, Ā pAā‚ = 60.79 kPa

Partial pressure of Methane at point 0.02 m away, Ā pAā‚‚ Ā = 20.26 kPa

Now,

Molar flux is given as:

[tex]J_A^* = -D_{AB} \times\frac{pA_2 - pA_1}{RT(z_2 - z_1)}[/tex]

Here,

[tex]D_{AB}[/tex]= 0.675 Ɨ 10ā»ā“ mĀ²/s (for He-CH4 at 101.32 kPa and 298 K)

Zā‚‚ - Zā‚ = 0.02 m

R is the ideal gas constant = 8.314 J/mol.K

T is the temperature = Ā 298 K

On substituting the respective values, we get

[tex]J_A^* = -0.675\times10^{-4} \times\frac{20.26 - 60.79}{8.314\times298(0.02)}[/tex]

or

= 5.521 Ɨ 10ā»Ā² mol/mĀ².s

Otras preguntas