Answer:
b > -3
Step-by-step explanation:
You are given two fractions:
[tex]\dfrac{2b-1}{2}\ \text{and }\ \dfrac{1+5b}{4}[/tex]
Find the difference of these two fractions:
[tex]\dfrac{2b-1}{2}-\dfrac{1+5b}{4}\\ \\=\dfrac{2(2b-1)-(1+5b)}{4}\\ \\=\dfrac{4b-2-1-5b}{4}\\ \\=\dfrac{-b-3}{4}[/tex]
Now, find the values of bfor which the difference between the fractions is negative. Solve the inequality:
[tex]\dfrac{-b-3}{4}<0\\ \\-b-3<0\\ \\-b<3\\ \\b>-3[/tex]
