Given a quadratic equation
[tex]ax^2+bx+c=0[/tex]
The solutions are given by
[tex]\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
In your case,
[tex]a=1,\quad b=3,\quad c=1[/tex]
So, the solutions are
[tex]\dfrac{-3\pm\sqrt{9-4}}{2}=\dfrac{-3\pm\sqrt{5}}{2}[/tex]
So, the two solutions are
[tex]x_1 = \dfrac{-3+\sqrt{5}}{2},\quad x_2=\dfrac{-3-\sqrt{5}}{2}[/tex]
And they are approximated by
[tex]x_1\approx -0.38,\quad x_2\approx -2.62[/tex]
