Answer:Explained
Step-by-step explanation:
Given
[tex]\frac{1}{m}+\frac{1}{m+2}=\frac{a}{b}[/tex]
and [tex]c^2=a^2+b^2[/tex]
For m =6
[tex]\frac{1}{6}+\frac{1}{8}=\frac{a}{b}[/tex]
[tex]\frac{7}{24}=\frac{a}{b}[/tex]
[tex]a=\frac{7b}{24}[/tex]
[tex]c^2=\left [ \frac{7^2}{24^2} \right ]b^2+b^2[/tex]
[tex]c=\frac{25b}{24}[/tex]
Triplets are [tex]\left ( a,b,c\right ) [/tex]
[tex]\left ( 7,24,25\right )[/tex]
[tex]\left ( 14,48,50\right )[/tex]
[tex]\left ( 21,72,75\right )[/tex]
