Answer:
5 blocks
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for AC
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
AC² = AB² + BC² ← substitute values
AC² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
AC = [tex]\sqrt{25}[/tex] = 5
