Respuesta :

EjerciciosFyQ
The distance covered will be:

[tex]d = v_0\cdot t + \frac{1}{2}a\cdot t^2 = 20\frac{m}{s}\cdot 5\ s + \frac{5}{2}\frac{m}{s^2}\cdot 5^2\ s^2 = \bf 162,5\ m[/tex]

The correct answer is D).

The Correct answer to this question for Penn Foster Students is: 137.5 m