Answer:
[tex](x^n + 2)(x^n + 8)[/tex]
Step-by-step explanation:
The polynomial [tex]x^{2n}+10x^n + 16[/tex] can be factored exactly the same as the polynomial [tex]x^2 + 10x + 16[/tex]. Here it factors into two numbers which multiply to 16 but add to 8. These factors are 8 and 2. So it factors into the expression (x+8)(x+2).
For the polynomial [tex]x^{2n}+10x^n + 16[/tex] it factors into the same factors except x ^n is used instead. The factors are [tex](x^n + 2)(x^n + 8)[/tex]
