Answer:
[tex]\large\boxed{t>\dfrac{1}{2}\to t\in\left(\dfrac{1}{2},\ \infty\right)}[/tex]
Step-by-step explanation:
[tex]9(t-2)>3(t-7)\qquad\text{use distributive property}\\\\(9)(t)+(9)(-2)>(3)(t)+(3)(-7)\\\\9t-18>3t-21\qquad\text{add 18 to both sides}\\\\9t>3t-3\qquad\text{subtract 3t from both sides}\\\\6t>3\qquad\text{divide both sides by 6}\\\\t>\dfrac{3}{6}\\\\t>\dfrac{1}{2}[/tex]
