Answer:
[tex]\boxed{a.\:\:\:60\degree}[/tex]
Step-by-step explanation:
The given trigonometric equation is
[tex]5\tan(x)=5\sqrt{3}[/tex] for [tex]0\degree \le x\le 180\degree[/tex].
We divide through by 5 to get;
[tex]\tan(x)=\sqrt{3}[/tex]
We take the inverse tangent of both sides to obtain;
[tex]x=tan^{-1}(\sqrt{3})[/tex]
[tex]x=60\degree[/tex]
Since the tangent ratio is positive, it means [tex]x[/tex] could also be in the 3rd quadrant. But this is outside the given range.
Therefore the correct answer is A
