anayamulay
anayamulay anayamulay
  • 01-02-2019
  • Mathematics
contestada

Please solve this
364x-64x=300x
and
12(x2–x–1)+13(x2–x–1)=25(x2–x–1)

Respuesta :

caycejogomez22
caycejogomez22 caycejogomez22
  • 01-02-2019

Answer:


Step-by-step explanation:

All real numbers are solutions in both.

12(x2−x−1)+13(x2−x−1)=25(x2−x−1)

Step 1: Simplify both sides of the equation.

25x2−25x−25=25x2−25x−25

Step 2: Subtract 25x^2 from both sides.

25x2−25x−25−25x2=25x2−25x−25−25x2

−25x−25=−25x−25

Step 3: Add 25x to both sides.

−25x−25+25x=−25x−25+25x

−25=−25

Step 4: Add 25 to both sides.

−25+25=−25+25

0=0



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