16y(2−y)+(4y−5)(2)=0
Step 1: Simplify both sides of the equation.
−16y2+40y−10=0
Step 2: Use quadratic formula with a=-16, b=40, c=-10.
y=−b±√b2−4ac2a
y=−(40)±√(40)2−4(−16)(−10)2(−16)
y=−40±√960−32
y=54+−14√15 or y=54+14√15
Answer:
y=54+−14√15 or y=54+14√15
