The answer is: the compound's empirical formula is CH₂.
m(C) = 36.04 g; mass of carbon.
M(C) = 12.01 g/mol; molar mass of carbon.
n(C) = m(C) ÷ M(C).
n(C) = 36.04 g ÷ 12.01 g/mol.
n(C) = 3 mol; amount of carbon.
m(H) = 6.04 g; mass of hydrogen.
n(H) = 6.04 g ÷ 1.007 g/mol.
n(H) = 6 mol; amount of hydrogen.
n(C) : n(H) = 3 mol : 6 mol.
n(C) : n(H) = 1 mol : 2 mol.
