Answer:
[tex]\boxed{x = \frac{1}{2}} \text{and} \boxed{x = - 1}[/tex]
Step-by-step explanation:
The quadratic formula is: [tex]$\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$[/tex].
So plugging in all the values, we are left with [tex]\frac{-1 \pm 3}{4}.[/tex]
Then, we can solve for both values of x, which are [tex]x = 1/2[/tex] and [tex]x = -1[/tex]
