[tex] \bf \textit{Logarithm Cancellation Rules}
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log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
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\textit{Logarithm of rationals}
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log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
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\rule{34em}{0.25pt}\\\\
log(x)-log(6)=2\implies log\left(\cfrac{x}{6} \right)=2\implies log_{10}\left(\cfrac{x}{6} \right)=2
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10^{log_{10}\left(\frac{x}{6} \right)}=10^2\implies \cfrac{x}{6}=10^2\implies x=600 [/tex]
