Answer : 108 kJ of heat is absorbed
Explanation :
Enthalpy of vaporization of water at body temperature is 2.41 kJ/g
That means we need 2.41 kJ to evaporate 1 gram of sweat.
Let us use this as a conversion factor to find the amount of heat needed to evaporate 45 grams of sweat.
The equation can be set as follows.
[tex]45gSweat \times \frac{2.41 kJ}{g} = 108 kJ[/tex]
Therefore we can say that 108 kJ of heat is absorbed when sweat is evaporated from someone's skin.
