Refer to the attached image.
As we can observe ABCD is a square, whose corners that is A,B,C and D lie on the circle.
The diameter AC = 0.35 meter.
We have to find the side of square.
Let the measure of side of a square be 'l' meter
In triangle ABC,
By Pythagoras theorem, we get
[tex](AC)^2 = (AB)^2 + (BC)^2[/tex]
[tex](0.35)^2 = (l)^2 + (l)^2[/tex]
[tex](0.35)^2 = 2(l)^2[/tex]
[tex]\frac{(0.35)^2}{2} = (l)^2[/tex]
[tex]l^2 = 0.06125[/tex]
So, l = 0.25 meter
Therefore, the measure of side of the square is 0.25 meter.
