Respuesta :

we are given

[tex] BQ=10 [/tex]

and we have to find BF

we know that

point Q is centroid

and centroid always leaves median in 2:1

so,

[tex] BQ=\frac{2}{3} *BF [/tex]

now, we can plug BQ=10

[tex] 10=\frac{2}{3} *BF [/tex]

we can solve for BF

[tex] BF=10*\frac{3}{2} [/tex]

so, we get

[tex] BF=15 [/tex]..............Answer

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