Respuesta :

DeanR
There are two ways to do this, solve the equation or try all the answers.  I'll solve.

[tex]18=(x-2)(x+5)=x^2+3x-10[/tex]

[tex]0=x^2+3x-28[/tex]

[tex]0=(x+7)(x-4)[/tex]

[tex]x=-7\quad \textrm{or} \quad x=4[/tex]

Choice B, [tex]x=-7[/tex]

The other root was not among the choices.


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