victoria38baby
victoria38baby victoria38baby
  • 02-06-2018
  • Mathematics
contestada

what are the zeros of the polynomial x2+4x-12

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caylus
caylus caylus
  • 02-06-2018
Hi,
[tex]x^2+4x-12=0\\ \Rightarrow\ x^2+6x-2x-12=)0\\ \Rightarrow\ x(x+6)-2(x+6)=0\\ \Rightarrow\ (x+6)(x-2)=0\\ \boxed{\Rightarrow\ x=-6\ or\ x=2}\\ [/tex]
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